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56 = 15,625 so 15,6251/6 = 5 37 = 2,187 so ( 2,187)1/7 = 3 ( 5)9 = 1,953,125, so ( 1,953,125)1/9 = 5 64 = 1,296 so 1,2961/4 = 6 ( 6)4 = 1,296 so 1,2961/4 = 6 What The radical notation can be used for any integer root For the 1/n power, a small numeral n is placed in the upper left part of the radical symbol If you use this notation, you must be sure that the radical symbol extends completely over the quantity of which you want to take the root If you use the fractional notation, parentheses, brackets, and braces should be used to define the quantity of which you want to take the root

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Now you will ask, Can 6 and 6 both be valid 4th roots of 1,296 The answer is Yes Both 6 and 6 will work here: 6 6 6 6 = 1,296 and ( 6) ( 6) ( 6) ( 6) = 1,296 If you multiply any negative number by itself an even number of times, you ll get a positive number Therefore, if you have some number a and its additive inverse a, and then you raise both of those numbers to an even positive integer power p, you will get ( a)p = a p every time! If we call ( a)p or a p by some other name such as b, then the pth root of b is ambiguous That would mean, for example, 161/4 = 2 and 2 811/4 = 3 and 3 15,6251/6 = 5 and 5 It could even mean something as simple, and yet as troubling, as 11/2 = 1 and 1 Mathematicians get around this problem by saying that whenever two numbers at once are the result of a reciprocal power, the positive value is the correct one, unless otherwise specified That means 161/4 = 2 811/4 = 3

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The new measurement is modeled as ym+1 = Hm+1 x + m+1 , where var( m+1 , j ) = Rm+1,j m+1,j for all j (Rm+1 will be used as a short hand notation for Rm+1,m+1 in the following) Therefore, the information available for estimating x after measurement m+1 is xm and ym+1 which can be organized as xm ym+1 = = x xm , Hm+1 x + m+1 (534) (535)

15,6251/6 = 5 11/2 = 1 You can indicate that you want to use the negative value by placing minus signs like this: (161/4) = 2 (811/4) = 3 (15,6251/6) = 5 (11/2) = 1 Sometimes you will actually want to let either the positive or the negative value be used In cases of that sort, you should throw a plus-or-minus sign ( ) into the mix, like this: (161/4) = 2 (811/4) = 3 (15,6251/6) = 5 (11/2) = 1 Here s another possible confusion-maker Always pay special attention to where the parentheses are placed if you see a negative number raised to a power Also, be careful if there are no parentheses at all If there s any doubt, it s best to place extra parentheses in an expression so everyone knows exactly what it means For example, ( 2)3 = ( 2) ( 2) ( 2) = 8 and 23 = (23) = (2 2 2) = 8 In contrast to this, ( 2)4 = ( 2) ( 2) ( 2) ( 2) = 16 but 24 = (24) = (2 2 2 2) = 16

Constructing a hypothetical set of m + 1 measurements yields xm ym+1 = I Hm+1 x+ xm m+1 (536)

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Negative reciprocal powers We still have not explored what happens when we raise a number to a negative reciprocal-ofinteger power You can probably figure out the meaning of an expression such as 125 1/3, or

which has the form of eqn (517) Therefore it can be solved using eqns (527-528) by de ning the weighting matrix R 1 corresponding to cov([ xm , m+1 ]) Eqn (528) results in: P 1 m+1 P 1 m+1 = = I Hm+1 Pm 0 0 Rm+1

125 to the 1/3 power You take the 1/3 power of 125, which is 5, and then take the reciprocal of that, which is 1/5 Mathematically, it goes like this: 125 1/3 = 125 (1/3) = 1/(1251/3) = 1/5

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